If two triangles have two angles of the one equal to two angles of the other, each to each, and one side equal to one side, viz. either the sides adjacent to the equal... The Elements of Euclid - Page 80by Euclid - 1838 - 416 pagesFull view - About this book
| John Keill - Logarithms - 1723 - 364 pages
...Angle HAC is alfo equal to the Angle MDF. Therefore the two Triangles MDF, HAC, have two Angles of the **one equal to two Angles Of the other, each to each, and** one Side of the one equal to one Side of the other, viz. that which is fubtended by one of the equal... | |
| John Keill - Trigonometry - 1733 - 397 pages
...Angle HAG is alfo equa to the Angle MDF. Therefore the two Triangles MDF, HA C, have two Angles of the **one equal to two Angles of the other, each to each, and** one Side of the one equal to one Side of the other, viz. that which is fubtended by one of the equal... | |
| Euclid, Edmund Stone - Geometry - 1765 - 464 pages
...Clavius has alfo tranflated them into Latin. PROP. XXVI. THEO R. If two triangles have two angles of the **one equal to two angles of the other, each to each, and** one fide of the one equal to one fide of the other, either that fide which is hetween the equal angles,... | |
| Robert Simson - Trigonometry - 1775 - 520 pages
...HCF is equal to KCF, and the right angle FHC equal to the right angle FKC; in the triangles FHC, FKC **there are two angles of one equal to two angles of the other,** and the fide FC, which is oppofite to one of the equal angles in each, is common to both ; therefore... | |
| Euclid - 1781 - 520 pages
...Fl angle FCK is equal to the right angle FCL : Therefore, in the two triangles FKC, FLC, there ate **two angles of one equal to two angles of the other, each** t» each, and the fide FC, which is adjacent to the equal angles in each, is common to both ; theiefore... | |
| Euclid, John Playfair - Electronic book - 1795 - 400 pages
...HCF is equal to KCF, and the right angle FHC equal to the right angle FKC ; in the triangles FHC, FKC **there are two angles of one equal to two angles of the other,** and the fide FC, which is oppofite to one of the equal angles in each, is common to both ; therefore... | |
| Benjamin Donne - 1796
...remaining angle of me nwji be equal to the remaining angle of the other. THEOREM 15. If two triangles have **two angles of one equal to two angles of the other, each to each, and** one s1de of one equal to one D side side of the other, the triangles are equal in every refpcEl. —... | |
| Alexander Ingram - Trigonometry - 1799 - 351 pages
...Cv.ED 84. i. b 34. i. PROP. BooK I. 54.i, PROP. XXVI. THEOR. TF two triangles have two angles of the **one equal to -*- two angles of the other, each to each ; and** one fide equal to one fide, viz. either the fides adjacent to the equal angles, or the fides oppofite... | |
| Robert Simson - Trigonometry - 1804
...HCF is equal to KCF, and the right angle FHC equal to the right angle FKC ; in the triangles FHC, FKC **there are two angles of one equal to two angles of' the other** ; and the fide FC, which is oppofite to one of the equal angles in each, is common to both ; therefore... | |
| Euclides - 1816 - 528 pages
...HCF is equal to KCF, and the right angle FHC equal to the right angle FKC ; in the triangles FHC, FKC **there are two angles of one equal to two angles of the other,** and the side FC, which is opposite to one of the equal angles in each, is d 26. 1. common to both ;... | |
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