Handbook of the Steam-engine |
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Page 10
... amount of the quantity that has to be expressed . For example , if we hold up 5 fingers of the one hand and 3 of the other , and are asked how much 5 and 3 amount to , we at once see that the number is 8 , as we either actually or ...
... amount of the quantity that has to be expressed . For example , if we hold up 5 fingers of the one hand and 3 of the other , and are asked how much 5 and 3 amount to , we at once see that the number is 8 , as we either actually or ...
Page 13
... amount to any considerable number , into groups of three each , by means of a comma interposed . But the comma in no way affects the value of the quantity , but is merely used to save the trouble of counting the figures to make sure ...
... amount to any considerable number , into groups of three each , by means of a comma interposed . But the comma in no way affects the value of the quantity , but is merely used to save the trouble of counting the figures to make sure ...
Page 14
... amount of the sum subtracted or the sum left . Thus 50—30 = 20 ; or if we take the successive stages , we have 50-5 = 45 , and 45 1530 , and 30 10 = 20 , which is the same result as before . S GENERAL EXPLANATION OF THE METHOD OF ...
... amount of the sum subtracted or the sum left . Thus 50—30 = 20 ; or if we take the successive stages , we have 50-5 = 45 , and 45 1530 , and 30 10 = 20 , which is the same result as before . S GENERAL EXPLANATION OF THE METHOD OF ...
Page 29
... amount by 10 , so by abstracting a cipher from the end of any number we divide its amount by 10. Thus 2 × 10-20 and 20 × 10-200 . So also 200-10-20 and 20 ÷ 10-2 . If , therefore , we have a divisor containing a number of ciphers , we ...
... amount by 10 , so by abstracting a cipher from the end of any number we divide its amount by 10. Thus 2 × 10-20 and 20 × 10-200 . So also 200-10-20 and 20 ÷ 10-2 . If , therefore , we have a divisor containing a number of ciphers , we ...
Page 53
... amount of labour may be saved in performing arithmetical computations , and to facilitate such computations the logarithms of all the numbers usually occurring in calculations have been ascertained and arranged in tables , so as to ...
... amount of labour may be saved in performing arithmetical computations , and to facilitate such computations the logarithms of all the numbers usually occurring in calculations have been ascertained and arranged in tables , so as to ...
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Common terms and phrases
40 inches 64 inches air-pump crosshead amount atmosphere beam body boiler breadth carbonic acid cast-iron centre chimney coal coefficient column condenser constant number crank in inches cube root cubic feet cubic foot cubic inches cylinder in inches decimal denominator diagram taken diameter of cylinder dimensions divisor engine equal Example 1.-Let 40 Example 2.-Let 64 Example 2.-What Fahrenheit feet per second figure FIND THE PROPER flue fly-wheel fraction furnace gibs and cutter given heating surface horse-power hour inch of section inches diameter latent heat logarithm motion moving pence pendulum pipe piston rod pounds proper depth proper diameter proper thickness proportion pump quantity quotient resistance revolutions per minute RULE.-Multiply the diameter screw sectional area shaft shillings side lever side rod specific heat speed square feet square inch square root strength stroke subtract temperature tion tubes valve velocity vessel vulgar fraction water-line weight wheel
Popular passages
Page 211 - Constant of an engine is found by multiplying the area of the piston in square inches by the speed of the piston in feet per minute and dividing the product by 33,000. It is the power the engine would develop with one pound mean effective pressure. To find the horse-power of the engine, multiply the MEP of the diagram by this constant.
Page 278 - Rule : Multiply the square of the diameter of the cylinder in inches by the cube root of the stroke in feet, and divide the product by 47. The quotient is the nominal horse-power of the engine.
Page 103 - ... is the same as that which a heavy body would acquire in falling from the height of an atmosphere composed of the gas in question of uniform density throughout.