Handbook of the Steam-engine |
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Page 5
... follows : a half , ; a quarter , ; an eighth , ; a six- teenth , and a tenth , . The figure above the line is called the numerator , because it fixes the number of halves , quarters , or eighths , which is intended to be expressed ; and ...
... follows : a half , ; a quarter , ; an eighth , ; a six- teenth , and a tenth , . The figure above the line is called the numerator , because it fixes the number of halves , quarters , or eighths , which is intended to be expressed ; and ...
Page 8
... follows that there will be 12 times 144 , or , in all , 1,628 cubic inches in the cubic foot . So , in like manner , as there are 3 lin- ear feet in the linear yard , and 9 square feet in the square yard , there will be 3 times 9 or 27 ...
... follows that there will be 12 times 144 , or , in all , 1,628 cubic inches in the cubic foot . So , in like manner , as there are 3 lin- ear feet in the linear yard , and 9 square feet in the square yard , there will be 3 times 9 or 27 ...
Page 12
... follows : 2708 1904 Here , beginning at the right - hand column , we say 8 9899 and 7 are 15 , and 9 are 24 , and 4 are 28. We write the 5467 8 under the column of units , and carry the 2 tens to the next column of tens . Adding up this ...
... follows : 2708 1904 Here , beginning at the right - hand column , we say 8 9899 and 7 are 15 , and 9 are 24 , and 4 are 28. We write the 5467 8 under the column of units , and carry the 2 tens to the next column of tens . Adding up this ...
Page 15
... follows : 67 59 = Here we say we cannot subtract 8 from 7 , so that we must borrow 1 from the previous column , which , when imported into the column of units , will be 10 ; and we therefore say 8 taken from 17 leaves 9 , which 9 we ...
... follows : 67 59 = Here we say we cannot subtract 8 from 7 , so that we must borrow 1 from the previous column , which , when imported into the column of units , will be 10 ; and we therefore say 8 taken from 17 leaves 9 , which 9 we ...
Page 17
... follows : 1 = 1 1 + 1 = 2 1 + 1 + 1 = 3 1 + 1 + 1 + 1 = 4 1 + 1 + 1 + 1 + 1 = 5 There are certain numbers which are formed by the contin- ued addition of other numbers than 1 ; and the numbers which are formed by the continued addition ...
... follows : 1 = 1 1 + 1 = 2 1 + 1 + 1 = 3 1 + 1 + 1 + 1 = 4 1 + 1 + 1 + 1 + 1 = 5 There are certain numbers which are formed by the contin- ued addition of other numbers than 1 ; and the numbers which are formed by the continued addition ...
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Common terms and phrases
40 inches 64 inches air-pump crosshead amount atmosphere beam body boiler breadth carbonic acid cast-iron centre chimney coal coefficient column condenser constant number crank in inches cube root cubic feet cubic foot cubic inches cylinder in inches decimal denominator diagram taken diameter of cylinder dimensions divisor engine equal Example 1.-Let 40 Example 2.-Let 64 Example 2.-What Fahrenheit feet per second figure FIND THE PROPER flue fly-wheel fraction furnace gibs and cutter given heating surface horse-power hour inch of section inches diameter latent heat logarithm motion moving pence pendulum pipe piston rod pounds proper depth proper diameter proper thickness proportion pump quantity quotient resistance revolutions per minute RULE.-Multiply the diameter screw sectional area shaft shillings side lever side rod specific heat speed square feet square inch square root strength stroke subtract temperature tion tubes valve velocity vessel vulgar fraction water-line weight wheel
Popular passages
Page 211 - Constant of an engine is found by multiplying the area of the piston in square inches by the speed of the piston in feet per minute and dividing the product by 33,000. It is the power the engine would develop with one pound mean effective pressure. To find the horse-power of the engine, multiply the MEP of the diagram by this constant.
Page 278 - Rule : Multiply the square of the diameter of the cylinder in inches by the cube root of the stroke in feet, and divide the product by 47. The quotient is the nominal horse-power of the engine.
Page 103 - ... is the same as that which a heavy body would acquire in falling from the height of an atmosphere composed of the gas in question of uniform density throughout.