Handbook of the Steam-engine |
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Page 30
John Bourne. dend and divide the number thus obtained by the divisor . Place the quotient under the second figure of the dividend ... denominator is exactly equal to 1 , and therefore NATURE AND PROPERTIES OF FRACTIONS . 31 such a fraction 30 ...
John Bourne. dend and divide the number thus obtained by the divisor . Place the quotient under the second figure of the dividend ... denominator is exactly equal to 1 , and therefore NATURE AND PROPERTIES OF FRACTIONS . 31 such a fraction 30 ...
Page 32
... dividend 1 by the quotient , which is equal to nothing , we obtain again the divisor ... numerator of each divided by the denominator gives 2. So likewise the ... multiply numerator and denominator by the same number . Thus in the case of the ...
... dividend 1 by the quotient , which is equal to nothing , we obtain again the divisor ... numerator of each divided by the denominator gives 2. So likewise the ... multiply numerator and denominator by the same number . Thus in the case of the ...
Page 40
... denominator , the division takes place only with respect to the numerators . An inch being of a foot , it is clear ... Multiply the numerator of the dividend by the denom- inator of the divisor for the new numerator , and the denomi ...
... denominator , the division takes place only with respect to the numerators . An inch being of a foot , it is clear ... Multiply the numerator of the dividend by the denom- inator of the divisor for the new numerator , and the denomi ...
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Common terms and phrases
40 inches 64 inches air-pump crosshead amount atmosphere beam body boiler breadth carbonic acid cast-iron centre chimney coal coefficient column condenser constant number crank in inches cube root cubic feet cubic foot cubic inches cylinder in inches decimal denominator diagram taken diameter of cylinder dimensions divisor engine equal Example 1.-Let 40 Example 2.-Let 64 Example 2.-What Fahrenheit feet per second figure FIND THE PROPER flue fly-wheel fraction furnace gibs and cutter given heating surface horse-power hour inch of section inches diameter latent heat logarithm motion moving pence pendulum pipe piston rod pounds proper depth proper diameter proper thickness proportion pump quantity quotient resistance revolutions per minute RULE.-Multiply the diameter screw sectional area shaft shillings side lever side rod specific heat speed square feet square inch square root strength stroke subtract temperature tion tubes valve velocity vessel vulgar fraction water-line weight wheel
Popular passages
Page 211 - Constant of an engine is found by multiplying the area of the piston in square inches by the speed of the piston in feet per minute and dividing the product by 33,000. It is the power the engine would develop with one pound mean effective pressure. To find the horse-power of the engine, multiply the MEP of the diagram by this constant.
Page 278 - Rule : Multiply the square of the diameter of the cylinder in inches by the cube root of the stroke in feet, and divide the product by 47. The quotient is the nominal horse-power of the engine.
Page 103 - ... is the same as that which a heavy body would acquire in falling from the height of an atmosphere composed of the gas in question of uniform density throughout.