...force acting on the particle m' and so on, so that the right920351A hand member of this equation is the sum of the .^-components of all the forces acting on the particles of the system, and this is equal to the sum of the ^-components of all of the external forces...

...of the force acting on the particle m' and so on, so that the right" hand member of this equation is the sum of the ^-components of all the forces acting on the particles of the system, and this is equal to the sum of ^-components of all of the external forces...

...equals rQ2 (Art. 32). Hence, according to the principle of the motion of the mass-center (Art. 34), the sum of the components of all the forces (acting on the gyrostat) along radius of the circle (through the mass-center perpendicular to the precession-axis)...

...35). Therefore the resultant has no component at right angles to the line of motion; or, the algebraic sum of the components of all the forces acting on the body along any line at right angles to the path equals zero. Thus, if the path is taken as an x axis and...

...determine the pressure transmitted by the plunger pump to the hydraulic press itself: Since the piston is in equilibrium, the sum of the components of all the forces acting on it is zero; />=• p • ^ - C = 79.6 ^ - W - 200 - 24,800 kgf - 24.S tf. ** § 14. Liquids which are...

...the force magnitude by the perpendicular distance of its line of action from the point considered. For such a body to be in equilibrium, the sum of the moments of forces tending to cause rotation in one direction must be equal to the sum of the rotating...