| William Suddards Franklin, Barry MacNutt - Mechanics - 1908 - 283 pages
...force acting on the particle m' and so on, so that the right920351A hand member of this equation is **the sum of the .^-components of all the forces acting on the** particles of the system, and this is equal to the sum of the ^-components of all of the external forces... | |
| William Suddards Franklin, Barry MacNutt - Heat - 1910 - 409 pages
...of the force acting on the particle m' and so on, so that the right" hand member of this equation is **the sum of the ^-components of all the forces acting on the** particles of the system, and this is equal to the sum of ^-components of all of the external forces... | |
| Edward Rose Maurer - Mechanics - 1914 - 356 pages
...equals rQ2 (Art. 32). Hence, according to the principle of the motion of the mass-center (Art. 34), **the sum of the components of all the forces (acting on the** gyrostat) along radius of the circle (through the mass-center perpendicular to the precession-axis)... | |
| Edward Rose Maurer - Mechanics - 1917 - 381 pages
...35). Therefore the resultant has no component at right angles to the line of motion; or, the algebraic **sum of the components of all the forces acting on the body** along any line at right angles to the path equals zero. Thus, if the path is taken as an x axis and... | |
| Aeronautics - 1959
...determine the pressure transmitted by the plunger pump to the hydraulic press itself: Since the piston is **in equilibrium, the sum of the components of all the forces acting on** it is zero; />=• p • ^ - C = 79.6 ^ - W - 200 - 24,800 kgf - 24.S tf. ** § 14. Liquids which are... | |
| Juvenile Nonfiction - 2003 - 2879 pages
...the force magnitude by the perpendicular distance of its line of action from the point considered. **For such a body to be in equilibrium, the sum of the** moments of forces tending to cause rotation in one direction must be equal to the sum of the rotating... | |
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