Structural and Stress AnalysisStructural analysis is the corner stone of civil engineering and all students must obtain a thorough understanding of the techniques available to analyse and predict stress in any structure. The new edition of this popular textbook provides the student with a comprehensive introduction to all types of structural and stress analysis, starting from an explanation of the basic principles of statics, normal and shear force and bending moments and torsion. Building on the success of the first edition, new material on structural dynamics and finite element method has been included. Virtually no prior knowledge of structures is assumed and students requiring an accessible and comprehensive insight into stress analysis will find no better book available.
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Contents
| 1 | |
| 20 | |
| 42 | |
CHAPTER 4 Analysis of Pinjointed Trusses | 81 |
CHAPTER 5 Cables | 114 |
CHAPTER 6 Arches | 133 |
CHAPTER 7 Stress and Strain | 150 |
CHAPTER 8 Properties of Engineering Materials | 188 |
CHAPTER 14 Complex Stress and Strain | 373 |
CHAPTER 15 Virtual Work and Energy Methods | 415 |
CHAPTER 16 Analysis of Statically Indeterminate Structures | 467 |
CHAPTER 17 Matrix Methods of Analysis | 548 |
CHAPTER 18 Plastic Analysis of Beams and Frames | 592 |
CHAPTER 19 Yield Line Analysis of Slabs | 625 |
CHAPTER 20 Influence Lines | 640 |
CHAPTER 21 Structural Instability | 684 |
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Common terms and phrases
acting actual analysis angle applied arch assumed axes axial beam beam section becomes bending moment cable Calculate cantilever carries Chapter column complete compression compressive stress concrete consider constant corresponding cross section deflection determine direct stress direction displacement distributed load effect elastic element energy equal equation equilibrium EXAMPLE expression failure FIGURE follows frame given gives Hence horizontal increase influence line internal joint length load material matrix maximum method negative Note obtain occurs plane plastic positive principle problems produced reinforcement respectively resultant rotation shape shear force shear stress shown in Fig solution span statically indeterminate steel stiffness strain structure subjected Substituting support reactions Suppose symmetry taking tensile tension truss unit load vertical virtual yield zero
Popular passages
Page 26 - The fact is, however, that if three forces meeting at a point are in equilibrium they may be represented in magnitude and direction by the three sides of a triangle drawn to scale.
Page 22 - If a moving point possess simultaneously velocities which are represented in magnitude and direction by the two sides of a parallelogram drawn from a point, they are equivalent to a velocity which is represented in magnitude and direction by the diagonal of the parallelogram passing through the point.
Page 30 - The moment of the couple about any point in the plane of the forces is equal to the product of one of the forces and the perpendicular distance between the lines of action of the forces.
Page 26 - In a similar way it can be shown that if any number of forces, in the same plane, acting at a point, are in equilibrium, they may be represented, in magnitude and direction, by the sides of a polygon taken in order.
Page 20 - Newton's first law of motion, which states that a body will remain in...
Page 34 - If we consider one arm rotating under uniform conditions, the sum of the moments of all the forces, acting on the roller and arm, about the point of support O will be zero (Fig.
Page 20 - ... that the mass of a body is a measure of the quantity of matter...
Page 33 - Since the piston is in equilibrium, the sum of the components of all the forces acting on it is zero; />=• p • ^ - C = 79.6 ^ - W - 200 - 24,800 kgf - 24.S tf.