THE UNIVERSAL MODERN CAMBIST, AND FOREIGN AND DOMSESTIC COMMERCIAL CALCULATOR; OR, A DICTIONARY OF NUMERICAL, ARITHMETICAL, AND MATHEMATICAL FACTS, TABLES, DATA, FORMULAS, AND PRACTICAL RULES FOR BUSINESS-MEN, MERCHANTS, BANKERS, BROKERS, AND ACCOUNTANTS.

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Page 144 - Multiply the divisor, thus augmented, by the last figure of the root, and subtract the product from the dividend, and to the remainder bring down the next period for a new dividend.
Page 13 - MONEY. 10 mills = 1 cent. 10 cents = 1 dime. 10 dimes = 1 dollar. 10 dollars = 1 eagle.
Page 96 - To reduce a compound fraction to an equivalent simple one. RULE. — Multiply all the numerators together for a numerator, and all the denominators together for the denominator, and they will form the simple fraction sought.
Page 96 - To reduce a whole number to an equivalent fraction, having a given denominator. RULE. Multiply the whole number by the given denominator, and place the product over the said denominator, and it will form the fraction required.
Page 100 - It will be seen that we multiply the denominator of the dividend by the numerator of the divisor for the denominator of the quotient, and the numerator of the dividend by the denominator of the divisor for the numerator of the quotient.
Page 111 - Sir," said I, after puzzling a long time over "more requiring more and less requiring less" — "will you tell me why I sometimes multiply the second and third terms together and divide by the first — and at other times multiply the first and second and divide by the third?" "Why, because more requires more sometimes, and sometimes it requires less — to be sure. Haven't you read the rule, my boy?" " Yes, sir, I can repeat the rule, but I don't understand it.
Page 71 - To find the head which will produce a given velocity of water through a pipe of a given diameter and length : Multiply the square of the velocity, expressed in feet per second, by the length of pipe multiplied by the quotient obtained by dividing 13.9 by the diameter of the pipe in inches, and divide the result obtained by 2,500.
Page 166 - Multiply continually together all the terms of the natural series of numbers, from 1 up to the given number, and the last product will be the answer.
Page 143 - ... and to the remainder bring down the next period for a dividend. 3. Place the double of the root already found, on the left hand of the dividend for a divisor. 4. Seek how often the divisor is contained in the dividend...
Page 59 - To find the capacity of a cask in gallons. Multiply the square of the mean diameter, in inches, by the length, in inches; and the product multiplied, by 0034 will give the capacity in liquid or wine gallons.

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