Young Scientist: A Practical Journal for Amateurs, Volume 1

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Industrial Publication Company., 1851

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Page 12 - The square described on the hypothenuse of a rightangled triangle is equal to the sum of the squares described on the other two sides.
Page 345 - If you divide it by 3? By 4? By 5? By 6? By 7? By 8?
Page 12 - If two triangles have two sides of the one equal to two sides of the...
Page 187 - ... most compact and useful, perhaps, that has yet been invented. It consists of a number of concentric grooves, whose respective diameters are regulated by the quantity of cord which must pass over their peripheries in equal spaces of time. In this system and all others where a single cord is employed, the power is to the weight as .1 to the number of parts of the cord acting on the lower block, or as 1 to twice the number of pullies in the lower block, and as in the system shown by Fig. 24, the...
Page 20 - The spherical excess of any spherical polygon is equal to the excess of the sum of its angles over two right angles taken as many times as the polygon has sides, less two.
Page 12 - Each side about the right angle is a mean proportional between the whole hypotenuse and the adjacent segment.
Page 68 - Hence a straight line drawn from the vertex of an isosceles triangle, to the middle of the base, is perpendicular to that base, and divides the vertical angle into two equal parts.
Page 87 - The geographical longitude of a place is the arc of the equator intercepted between the...
Page 12 - The measure of each angle of an equilateral triangle is 60°. 11. a. A triangle that has a right angle is called a right triangle. b. In a right triangle, the two acute angles are complementary. c.
Page 206 - To find the time in which pendulums of different lengths would vibrate, that which vibrates seconds being 39.2 inches. The time of the vibrations of pendulums are to each other, as the square roots of their lengths ; or, their lengths are as the squares of their times of vibrations. RULE. As the square of one second is to the square...

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