The engineers' manual of the Local marine examinations |
From inside the book
Results 1-5 of 70
Page 156
... space of time 7 navvies can do the work of 10 soldiers ? The arrangement of the work is as follows : - hours per day length , miles breadth , feet depth , feet soldiers instead of navvies 6 : ro 20 : 10 20 : 30 :: 1500 men : Answer ...
... space of time 7 navvies can do the work of 10 soldiers ? The arrangement of the work is as follows : - hours per day length , miles breadth , feet depth , feet soldiers instead of navvies 6 : ro 20 : 10 20 : 30 :: 1500 men : Answer ...
Page 158
... space of 41 of the first . IO . II . 12 . A plate of copper 2 ft . long , 9 in . wide , and 2 in . thick , is rolled into a sheet 3 ft . 6 in . wide and 18 ft . long ; how thick will it be ? Bar iron 1 in . square and 22 ft . long is ...
... space of 41 of the first . IO . II . 12 . A plate of copper 2 ft . long , 9 in . wide , and 2 in . thick , is rolled into a sheet 3 ft . 6 in . wide and 18 ft . long ; how thick will it be ? Bar iron 1 in . square and 22 ft . long is ...
Page 178
... space contained within its extremes or bounds , without any regard to thickness . The area or the content of the plane figure is estimated by the number of little squares that may be contained in it , the side of these little measuring ...
... space contained within its extremes or bounds , without any regard to thickness . The area or the content of the plane figure is estimated by the number of little squares that may be contained in it , the side of these little measuring ...
Page 187
... space included between the circumferences of two concentric circles . RULE LXXIX . 1 ° . Multiply the square of the greater diameter by 7854 for the area . 2o . Multiply the square of the inner diameter by · 7854 for the area . 3. From ...
... space included between the circumferences of two concentric circles . RULE LXXIX . 1 ° . Multiply the square of the greater diameter by 7854 for the area . 2o . Multiply the square of the inner diameter by · 7854 for the area . 3. From ...
Page 188
... space will it occupy on the deck ? Area 7854 × 58 × 52 = 2368 · 7664 square inches = 2368.7664 = 16 : 449 8q . feet . 4 ft . 10 in . 58 in . * 7854 4 ft . 4 in . 52 in . 3016 116 290 47124 7854 235620 3016 in . 144 { 12 ) 2368.7664 8q ...
... space will it occupy on the deck ? Area 7854 × 58 × 52 = 2368 · 7664 square inches = 2368.7664 = 16 : 449 8q . feet . 4 ft . 10 in . 58 in . * 7854 4 ft . 4 in . 52 in . 3016 116 290 47124 7854 235620 3016 in . 144 { 12 ) 2368.7664 8q ...
Other editions - View all
The Engineers' Manual of the Local Marine Examinations Thomas Liddell Ainsley No preview available - 2015 |
Common terms and phrases
air-pump Answer area of valve atmospheric line boiler bolts bottom cent centre circumference coal condenser contains cost crank cubic feet cubic foot cubic inches cyphers decimal denominator diagram distance divide dividend divisor effective pressure engine equal EXAMINATION PAPER-No EXAMPLES FOR PRACTICE exhaust figure fraction gallons heat high pressure horse-power hundred inches diameter inches of mercury indicator indicator diagram length of stroke lever mean effective pressure miles multiplicand multiply piston pitch plates port pounds pressure cylinder pressure of steam pressure per square pump quantity quotient ratio of expansion reduce remainder revolutions per minute rivets RULE safety-valve screw seams shaft side slide-valve specific gravity square feet square inch stays steam is cut subtract surface surface condenser tank temperature thickness thousand throughout the stroke tons total pressure tube vacuum vulgar fraction weight whole numbers
Popular passages
Page 42 - An Improper Fraction is one whose numerator is equal to or greater than its denominator ; as, f , -J.
Page 63 - Thus, reducing the two fractions to a common denominator, we multiply the numerator of the dividend by the denominator of the divisor, and the numerator of. the divisor by the denominator of the dividend ; (Art.
Page 139 - RULE. from half the sum of the three sides, subtract each side separately; multiply the half sum and the three remainders together, and the square root of the product will be the area required.
Page 56 - It is however impossible to find such a fraction unless all the given fractions be first expressed with a common denominator : for, since the denominator of a fraction expresses the number of equal parts into which the unit is divided, it follows that in two fractions which have not a common denominator the unit is not divided into the same number of equal parts : therefore in endeavouring to...
Page 239 - ... stroke have been performed, and the steam be at the same time throttled in the steam pipe, the full pressure of the steam within the cylinder cannot be maintained except near the beginning of the stroke where the piston travels slowly ; for as the speed of the piston increases, the pressure necessarily subsides, until the piston approaches the other end of the cylinder, where the pressure would rise again but that the operation of the lap on the valve by this time has had the effect of closing...
Page 239 - ... on the exhausting side, the port before the piston will be closed before that behind it is opened ; and the interval between the closing of the one and the opening of the other, will depend on the quantity of lap on the exhausting side of the valve.