The engineers' manual of the Local marine examinations |
From inside the book
Results 1-5 of 44
Page
... Temperature Questions relating to Strains , & c . .. .. 379 .. • 390 393 .. 395 402 .. 412 Questions relating to Friction On the Mechanical Powers : - The Lever - The Wheel and Axle - The Differential Axle - The Inclined Plane - The ...
... Temperature Questions relating to Strains , & c . .. .. 379 .. • 390 393 .. 395 402 .. 412 Questions relating to Friction On the Mechanical Powers : - The Lever - The Wheel and Axle - The Differential Axle - The Inclined Plane - The ...
Page
... Temperature .. Questions relating to Strains , & c . Questions relating to Friction On the Mechanical Powers : - .. .. .. .. .. .. 357 359 361 374 .. 376 • 377 379 390 393 .. 395 402 .. 412 The Lever - The Wheel and Axle - The ...
... Temperature .. Questions relating to Strains , & c . Questions relating to Friction On the Mechanical Powers : - .. .. .. .. .. .. 357 359 361 374 .. 376 • 377 379 390 393 .. 395 402 .. 412 The Lever - The Wheel and Axle - The ...
Page 197
... temperature of 60 ° as the standard of weight for all solids and liquids , and dry atmospheric air with the barometer at 30 inches as the standard of weight for gases . Water , however , seldom differs so much in specific gravity as to ...
... temperature of 60 ° as the standard of weight for all solids and liquids , and dry atmospheric air with the barometer at 30 inches as the standard of weight for gases . Water , however , seldom differs so much in specific gravity as to ...
Page 223
... temperature of 10 pounds steam and that of 25 pounds steam is 28 degrees : in what time will the pressure rise from the former to the latter pressure , if all the valves are shut and the fires in action ? ( In the calculation , neglect ...
... temperature of 10 pounds steam and that of 25 pounds steam is 28 degrees : in what time will the pressure rise from the former to the latter pressure , if all the valves are shut and the fires in action ? ( In the calculation , neglect ...
Page 223
... temperature of the steam at 10 lbs . and 28 lbs . = 28 ° Then if one lb. of coal heats 12000 lbs . of water 1o in 1a , it will raise 61031.25 lbs . 1800 in one hour . 20000 1031 1120 lbs . of coal will raise it 1120 X in one hour , that ...
... temperature of the steam at 10 lbs . and 28 lbs . = 28 ° Then if one lb. of coal heats 12000 lbs . of water 1o in 1a , it will raise 61031.25 lbs . 1800 in one hour . 20000 1031 1120 lbs . of coal will raise it 1120 X in one hour , that ...
Other editions - View all
The Engineers' Manual of the Local Marine Examinations Thomas Liddell Ainsley No preview available - 2015 |
Common terms and phrases
air-pump Answer area of valve atmospheric line boiler bolts bottom cent centre circumference coal condenser contains cost crank cubic feet cubic foot cubic inches cyphers decimal denominator diagram distance divide dividend divisor effective pressure engine equal EXAMINATION PAPER-No EXAMPLES FOR PRACTICE exhaust figure fraction gallons heat high pressure horse-power hundred inches diameter inches of mercury indicator indicator diagram length of stroke lever mean effective pressure miles multiplicand multiply piston pitch plates port pounds pressure cylinder pressure of steam pressure per square pump quantity quotient ratio of expansion reduce remainder revolutions per minute rivets RULE safety-valve screw seams shaft side slide-valve specific gravity square feet square inch stays steam is cut subtract surface surface condenser tank temperature thickness thousand throughout the stroke tons total pressure tube vacuum vulgar fraction weight whole numbers
Popular passages
Page 42 - An Improper Fraction is one whose numerator is equal to or greater than its denominator ; as, f , -J.
Page 63 - Thus, reducing the two fractions to a common denominator, we multiply the numerator of the dividend by the denominator of the divisor, and the numerator of. the divisor by the denominator of the dividend ; (Art.
Page 139 - RULE. from half the sum of the three sides, subtract each side separately; multiply the half sum and the three remainders together, and the square root of the product will be the area required.
Page 56 - It is however impossible to find such a fraction unless all the given fractions be first expressed with a common denominator : for, since the denominator of a fraction expresses the number of equal parts into which the unit is divided, it follows that in two fractions which have not a common denominator the unit is not divided into the same number of equal parts : therefore in endeavouring to...
Page 239 - ... stroke have been performed, and the steam be at the same time throttled in the steam pipe, the full pressure of the steam within the cylinder cannot be maintained except near the beginning of the stroke where the piston travels slowly ; for as the speed of the piston increases, the pressure necessarily subsides, until the piston approaches the other end of the cylinder, where the pressure would rise again but that the operation of the lap on the valve by this time has had the effect of closing...
Page 239 - ... on the exhausting side, the port before the piston will be closed before that behind it is opened ; and the interval between the closing of the one and the opening of the other, will depend on the quantity of lap on the exhausting side of the valve.